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Old June 4th, 2005, 4:11 PM   #1
 
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Default 60% chance out of 25 people, someone shares your birthday

Ok, my English isn't that good, but I'll try to explain. I hope I pick the right words.

When there are 26 (random) people in a bar, the chance that two of them share the same birthday, is 60%. That sound like bullshit, especially because there are 365 days and you are only with 26.

That's the beauty of the theory of probability.

What we are going to do, is to calculate the chance that nobody shares the same birthday. And then, we will distract (right term?) that chance from 100%.

Ok, here we go...

Step one
When there is only 1 person, the chance he does not share his birthday with anybody else is obviously 365/365.
When there is an extra 1 person, he can only have his birthday on the 364 other days. So the chance his birthday is on another day is 364/365.
When there enters a third person, the chance his birthday is on yet another day is 363/365.
...
You go on like that, and so the 26th person, has a 340/365 chance his birthday is not on the same day as the others.

Step two
Now we can calculate the chance that nobody shares the same birthday.
In the theory of probability, you have to multiply the seperate chances.
so: 365/365 x 364/365 x 363/365 x ... x 340/365 = 0.4 = 40%

Step three
So now we know that the chance nobody shares their birthday is 40%.
So the chance that two people out of 26 share their birthdays is 60%.

crazy, isn't it? images/smilies/smile.gif
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Old June 4th, 2005, 4:17 PM   #2
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ok we're in a virtual bar right here. my bday's is on may 9th WHOS IS THE SAME.?! (my guess is like 1)
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Old June 4th, 2005, 4:24 PM   #3
 
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I saw a program Brainiac yesterday hosted by Richard Hammond and he said the same.,.
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Old June 4th, 2005, 4:28 PM   #4
 
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Seriously? images/smilies/smile.gif
Hehe, well, I didn't see it, I know this from my statistics-course.

Don't try this at home. You will be dissapointed.
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Old June 4th, 2005, 4:40 PM   #5
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Your thread title is incorrect, it should read something like this:
"60% chance out of 26 people, 2 of them share a birthday" (not necessarily your birthday).

I think the changes of one of them sharing your birthday is something like this:
1. The chances of 1 other person sharing your birthday is 1 out of 365 (1/365).
2. The chance of a 2nd person sharing your birthday is also 1 out of 365, so combined for two people this is 2 out of 365 (2/365).
3. So the chances for 26 people (if you count yourself among them) is this:
(26-1) / 365 = 0.068 = 6.8%

Now it's been a lifetime ago since I took this kind of math in highschool (for which I got a near perfect score at the time), but still I could be wrong.
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Old June 4th, 2005, 5:05 PM   #6
 
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aahhh, reminds me of high school data management, I really liked that course
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Old June 4th, 2005, 5:06 PM   #7
 
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ESPNSTI you might be correct in some sense but you also have to consider the sample space. With the sample space you can truly identify the probability. Listing down the sample space would take ages though. 365P25.
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Old June 4th, 2005, 5:10 PM   #8
 
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oh god, how i hate probability threory and statics images/smilies/yucky.gif
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Old June 4th, 2005, 5:35 PM   #9
 
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I'm very sure about my statement.

1) I was told about it by a professor in mathematics
2) It is featured in the book: Guys and Science
3) It was featured on Dutch television on the national science quiz
4) Someone told me Hammond explained it in Brainiac.

images/smilies/smile.gif

By the way, I had theory of probability 6 hours a week for a whole year long on the university. It is very un-logical. So that's why it sounds wrong.
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Old June 4th, 2005, 5:46 PM   #10
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I wasn't saying your statement was incorrect, I was just saying that your title was.
The difference being:

The chances of 2 people sharing a birthday out of a pool of 26 people.

vs.

The chances of 1 or more people having the same birthday as yours out of a pool of 25 people.
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Old June 4th, 2005, 5:56 PM   #11
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What if we want to check for a shared birthday across two different calendars (i.e. solar and lunar calendars)? Then what's the probability? images/smilies/mrgreen.gif
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Old June 4th, 2005, 10:11 PM   #12
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Mmm, I think this is bullshit math.
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Old June 4th, 2005, 11:20 PM   #13
 
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In my high school class (long time ago images/smilies/wink.gif), this girl and I shared the same birth date. Exactly the same.
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Old June 4th, 2005, 11:20 PM   #14
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don't remind me that i have a stats exam on wednesday... images/smilies/mad.gif
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Old June 5th, 2005, 8:07 AM   #15
 
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Quote:
Originally Posted by jasonchiu
ok we're in a virtual bar right here. my bday's is on may 9th WHOS IS THE SAME.?! (my guess is like 1)
I'll go along with this game only cause mine is on the 12th of may and thats dam close...
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Old June 5th, 2005, 9:58 PM   #16
 
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04th June
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Old June 5th, 2005, 10:11 PM   #17
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mines 24th may....( turned 20 two weeks ago images/smilies/biggrin.gif )
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Old June 6th, 2005, 12:36 AM   #18
 
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Josty and I share the same birthday.... Anyone else born on the 25th december?
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Old June 6th, 2005, 12:42 AM   #19
 
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April 18th, here.
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Old June 6th, 2005, 12:46 AM   #20
 
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^^ my mum is april 18.

mine is oct 18
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