• The development of any software program, including, but not limited to, training a machine learning or artificial intelligence (AI) system, is prohibited using the contents and materials on this website.

Math

chaos386

chaos386

.sa = bad driver!
Joined
Nov 8, 2004
Messages
7,960
Location
Back in Saudia
Car(s)
SEAT Leon FR
The talk about the Google calculator in the thread "How much is 155MPH in KM/H??" got me in a mathematical mood, so let's talk math! :mrgreen:

Hey MXM, you mentioned Matlab in the other thread, do you use it? If so how is it? I've heard about it before and I used it for the first time earlier today (just to make a 3-D graph of Ym*Sin(kx - omega*t)).
 
I'm sure you are better in Math than I am, I can't solve this one.

a Log (x-5) = a? Log (7-x)

Can you solve this? it's really necessary for my test tomorrow, it's not in my book.

Thanks!
 
Yea, this is kinda painful subject. I'm on my 4th year in university, and I still have basic course 3 of math not passed. I tried 3 times :blush:

We use mostly Matlab and Mathematica, but I'm used to Matlab. It's great because of it's wide variety of toolboxes and easy but poferwul script lang.
Mathematica might be easier though, with it's friendly user interface, but IMHO not nearly as versatile.
 
Jostyrostelli said:
a Log (x-5) = a? Log (7-x)
Click to expand...

I assume these are complex logarithms? If so, I can't solve this either... Or too lazy finding out how they work :)

If they are real, it means x-5 = (7-x)^a, which doesn't look good either. And it looks like the thing is defined only in 5<x<7.

Sorry, I'm just as bad at Math :(
 
No I know what you mean by replacing numbers.

But that's this rule:

Log a^x = x Log a

But there are no rules about the a in [a log x], at least, not quadrating (sp?) it.

Thanks for replying anyway.
 
^ I say yes.

I'm going to be taking writing, world history, and algeo courses soon and I could probably use some outside ideas. :thumbsup:
 
I like math, but I wouldn't call myself a genius. I'm still only taking freshman calculus. The Log (x^a) = a Log x rule works in both directions and works with at least all real numbers (as long as x>0). I only got as far as MXM though. Not much I can do, unless you are given the value for a or something. :dunno:
 
^okey thanks for the answers! I found a nice big document with alot of mathematical rules, and it said the same, gonna make that one in a minute.

I'll make a homework thread tomorrow. Anxious to know what kindof questions you guys come up with.
 
And the final equation has a-numeber of roots, and those which are between 5 and 7 are good enough. Seems to be a little too complicated for a home work :dunno:

P.S. When x=6 it works for any a :)
 
Oh wait...I'm doing it again now...

And the a is not a random number like 5 times log...but it's the (don't know correct word in english). It's the a like in x?...it's the "macht" (power, wrong free translation)

The general rule is ^g Loga^b = b^g log a
The b is no normal number in my equation! It's the higher (x? one, it's the 2)

^aLog(x-5) = ^a? Log (7-x)

I can't believe that that rule can be used for this....or I'm mistaken...been a long day..

:unsure:
 
Pascal's Triangle. Just learned it yesterday.

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 22 15 6 1

Apparently you can use this to find lotsa stuff.
 
zyran said:
Pascal's Triangle. Just learned it yesterday.

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 22 15 6 1

Apparently you can use this to find lotsa stuff.
Click to expand...

Can you explain furhter? Does this have to do with my equation?
 
Pascals triangle is used mainly in expansions such as binomial series', which can be used to find approximate answers to some equations, amongst other things.
 
You must log in or register to reply here.
Top