#include <iostream.h>
#include <stdlib.h>
/* Name -
Date -
Program Name -
Program Description:
This Program will calculate the circle area, circumference, volume, and surface area of a cylinder
*/
//Constants
const double PI = 3.141592654;
//Function declarations
double circle_circumference(double radius);
double circle_area(double radius);
double cylinder_area(double radius, double height);
double cylinder_volume(double radius, double height);
//Main loop
int main()
{
double r, h, circumference, area, surface_area, volume;
char repeat;
// BEGIN WINDOWS COMMAND LINE-SPECIFIC CODE BLOCK
system("CLS");
// END WINDOWS COMMAND LINE-SPECIFIC CODE BLOCK
// Explain the program to the user
cout << "This program calculates the volume and surface area of a cylinder, as well as the area and circumference of its base. You can run as many different calculations as you like.\n\n";
do
{
// Get the input from the user
cout << "\n Enter the radius of the cylinder: ";
cin >> r;
cout << "Enter the height of the cylinder: ";
cin >> h;
// Calculate the info
circumference = circle_circumference(r);
area = circle_area(r);
surface_area = cylinder_area(r,h);
volume = cylinder_volume(r,h);
// Print the answers
cout << "The area of the base of the cylinder is " << area << ".\n";
cout << "The circumference of the base of the cylinder is " << circumference << ".\n";
cout << "The surface area of the cylinder is " << surface_area << ".\n";
cout << "The volume of the cylinder is " << volume << ".\n\n";
// Ask if they'd like to do it again
cout << "Would you like to do another calculation? (y/n) ";
cin >> repeat; // We just want the first letter
cin.ignore(80,'\n'); // Discard the rest, i.e. "es" or "o"
}
while (repeat == 'y' || repeat == 'Y');
return 0;
}
//Functions
double circle_circumference(double radius) {return 2*PI*radius;}
double circle_area(double radius){return PI*radius*radius;}
double cylinder_area(double radius, double height){return (2*PI*radius*radius + 2*PI*radius*height);}
double cylinder_volume(double radius, double height){return PI*radius*radius*height;}
)
That makes 3 solutions now in languages other than the one he wanted. Too funny.
